Monday, March 17, 2014

Experience from the mentoring program of Vic ICT for Women

Victorian ICT for Women organizes a mentoring program every year. They offer people from ICT industry to register their interest as to be mentor or mentee or both. This is an great opportunity for the women in IT industry to build up their networking as well as refine their leadership skill.

This year I have attended the program as a mentee with great intend to find my mentor. From whom I can learn a lot about the prospectus of IT industry and of course who can guide me for a successful path in this era of competition.

At the very first time I was a bit nervous about attending the program but when I joined the event it went smoothly. I enjoyed the whole time I spent there, learned about many people, had a chance to talk with some successful professionals.

The program was very well organized. At first the organizing member introduced us with the organizers and described us about the program's aim. Before the program every registered member had been asked to list their preferred mentors. After the introductory session, the mentor and the mentee got their chance to spend some time with their preferred one. It's called "Speed Dating Style". Ten minutes will be given to both of you to know about yourself. After that you will get chance to meet with your another preferred mentor.

It was an great opportunity to meet people from the ICT industry and do the networking. I liked my both mentors. They are very successful in their career and have full of experiences. Both of them gave me very useful tips and suggestion and shared some of their experience. It wish I could have both of their mentorship but unfortunately I had to choose one of them. Luckily, I got my mentor according to my choice and she is an wonderful lady and very much successful in her career. I am very much thankful to the Vic ICT for Women organization to give such an opportunity. 

Thursday, February 9, 2012

Git Installation in Ubuntu

Git is an open source version control system. It is designed to handle from small to very large projects with speed and efficiency.

Fig: Data flows and storage levels in Git

First install all the dependent packages

sudo aptitude build-dep git-core

Now download git-1.7.1.tar.gz

Now extract the file

sudo tar -xvzf git-1.7.1.tar.gz

If you download git-1.7.3.tar.bz2, then extract like this

sudo tar -xvjf git-1.7.3.tar.bz2

Now change the directory

cd git-1.7.x/

Run the following commands

sudo make install

Now check the version whether the git is properly installed-

git --version

Git tutorial -

User manual of Git -

Wednesday, February 8, 2012

Network configuration in Ubuntu

Open the file /etc/network/interfaces in vi mode or in different editor

sudo vi /etc/network/interfaces

Do the following changes –

auto lo
iface lo inet loopback

auto eth0
iface eth0 inet static

Now open the resolv.conf to add DNS settings

sudo vi /etc/resolv.conf

Do the following changes ---


You might need to remove dhcp-clinet3

sudo apt-get remove dhcp-client

Now restart the network

sudo /etc/init.d/networking restart

and also restart the network manager

sudo /etc/init.d/network-manager restart

Now ping to check whether your connection is ready.

Saturday, July 17, 2010

Experiencing Cryptographic Puzzle

I am a beginner in software testing. I had extreme curiosity about software testing. Now I am enjoying my work as a software tester.

Our team lead gave us a link of a puzzle

I am going to share my experience about it. In the first puzzle there were 46 characters with spaces. I calculate the frequency of both encoded and decoded message. Then I was looking at the hint to find out the key. I was looking at the triangle shape, after trying sometime I look over the hints. Then I concentrate the frequencies of the letter. I found that in the original message – “THE QUICK BROWN FOX JUMPED OVER THE LAZY DOG”, ‘S’ is missing and in the encoded message ‘Z’ is missing. This gave the clue and I assume ‘S’ as ‘Z’. Then I re-format the code with my idea – Offset= Position of ‘Z’ – Position of ‘S’. I found nothing interesting. Then I concentrate on finding two ‘THE’s. It was not caught by my eyes yet. Then I started writing the words with my formulated value. I found nothing yet!! I was supposed to give up finding. Then for the last time I started reading my code and searching the value in the encrypted message. There it is!! I found the message.

For the second puzzle it was also a challenging one. When I saw the challenge, it was already discovered! But I still tried to find out the decrypted message with my own idea. I have searched in google to find out pangrams. I have found many but selected some that will help me solve the puzzle. As in the encrypted message there are 41 letters. I remove those pangrams those are more than 41 letters.
  1. Big Fuji waves pitch enzymed kex liquor. (33 letters + 6 spaces)
  2. The quick brown fox jumps over a lazy dog. (33 letters + 8 spaces)
  3. Pack my box with five dozen liquor jugs. (32 letters + 7 spaces)
  4. Jackdaws love my big sphinx of quartz. (31 letters + 6 spaces)
  5. The five boxing wizards jump quickly. (31 letters + 6 spaces)
  6. How quickly daft jumping zebras vex. (30 letters + 6 spaces)
Now I have analyzed the frequencies of the letter. I have discarded the second pangram as Ben Kelly said that it’s another pangram. I consider 1 and 3 using my previous puzzle experience. He used there 2 dummy characters in the cipher before starting the original message. I was not sure about this. Now I’ve narrowed to two messages. I am not sure, whether I’m going to the right path or not. Now I’ve to find out the key. In the previous message he used 7 as offset value. I was thinking about the idea behind taking the offset value. I thought he considered the triangle as a rectangle triangle and according to Pythagorean Theorem square of hypotenuse of the triangle is the summation of the square of other two sides. I read about this in book regarding cryptography, that Pythagorean Theorem is used to make ciphers. I’ve found 5, 4, 3 letters in the sides of the triangle, I thought Ben took the offset adding the two sides (4 & 3) counts. Another thing is, in that code there are 9 blank spaces so, it thought it can be 9-2=7. For the new code, offset values I’ve taken considered are –
  • Length of the both sides of the rectangle – 10 & 4
  • Length of the max side – 11
  • Count of blank spaces (14-2) - 11
I found the pangrams taking offset value as 11!! I was wrong. The offset was not 11. It's 8. I did a mistake while listing the letter with offset value. I found the value by mistake! But it was not correct one. When I read Ben’s post, I came to know that my approach was pretty lengthy. He took a simple step- just the difference of starting two character’s position is the offset!!
I was really a great experience solving the puzzle. The lesson I have learn are -
  • Focus and defocus on the item what you are looking for.
  • Think simple and take simple step to explore the module.
  • Of course have some basic knowledge about the thing you are testing.
  • Utilize your previous experience of testing.
Thanks to Ben Kelly and Sajjadul Vaiya to appreciate my work.